


anyone tried it?

if your aware of it, but not keen, why not?





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ashley wrote:My understanding is that it will not stay mixed with petrol which is why you need to inject it seperately
jimGTS wrote:where to source e85?
i just thought it worth a go, wheres the harm![]()
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btw, i do have a water/meth kit lined up
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bobhatton wrote:jimGTS wrote:where to source e85?
i just thought it worth a go, wheres the harm![]()
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btw, i do have a water/meth kit lined up
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http://www.econol.co.uk/?gclid=CKCuqOjz ... tAodJEYA5g
.
jimGTS wrote:bobhatton wrote:jimGTS wrote:where to source e85?
i just thought it worth a go, wheres the harm![]()
![]()
btw, i do have a water/meth kit lined up
![]()
![]()
![]()
http://www.econol.co.uk/?gclid=CKCuqOjz ... tAodJEYA5g
.
btw, is this where you source it from and use this exact product?
could i get away with putting in a few ltrs per tank per fill up?
bobhatton wrote:jimGTS wrote:where to source e85?
i just thought it worth a go, wheres the harm![]()
![]()
btw, i do have a water/meth kit lined up
![]()
![]()
![]()
http://www.econol.co.uk/?gclid=CKCuqOjz ... tAodJEYA5g
Remember water injection only works in the combustion chamber by absorbing heat and lowering the pressure to stop detonation.If the engine is not detonating your power will drop.
It gives no cooling to the inlet air.
Injection point should be as close to the inlet valve in each manifold runner.
Methanol injection is a fuel and does nothing the same as water injection.![]()
with methanol your injection point can be back up the manifold runner but should be fitted into each one not one injector by the throttle body.
You will get some cooling of the inlet air and an increase in fuel octane.
Never get methanol on your skin, it is absorbed into the body and stored, your body does not get rid of it.Too much and it will kill you.
dazzz wrote:I'm no expert but
T.F.S. wrote:
Why do you keep spouting this stuff?
dazzz wrote:I'm no expert but
dazzz wrote:I'm no expert but
T.F.S. wrote:
MaCpT1+ MwHf
= MaCpT3
+ MwHg
T1=124C, T2=25C, T3=final Cp=Specific heat of air=1.005
Ma=mass of air/s, Mw=mass of water/s,
Hf=Enthalpy of sat liquid, Hg=Enthalpy of sat vapour
(obtained from steam tables)
Air mass=8.64/60= 0.144Kg/s.
We need to guess the final temperature of the mixture to look up tables:
Let T3=(T1+T2)/2=74.5°C.
say 75°C.
From the steam tables:
Hg@75°C
= 2635.3 kJ/kg Saturated vapour
Hf@25°C= 105kJ/Kg Saturated liquid
re-arrange the equation:
MaCp(T1-T3)= Mw(Hg-Hf)
to:
T3= 124-(2635.3-105)/(0.144*1.005)Mw= 17547Mw
Substitute Mw to obtain final temperature:
For Mw=0.00333Kg/s(200ml/min): T3=124-57.91=66.09°C
For Mw=0.00417kg/s(250ml/min): T3=124-73.12=50.88°C
For Mw=0.00500kg/s(300ml/min): T3=124-87.74=36.27°C
ashley wrote:kennym wrote:Same two people same subject same result, why?
Prove your respective arguments or agree to differ,
No offence to either but your past rudeness to each other detracts from you both.
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ashley wrote:By evaporating water into the inlet tract are we not displacing air, and by doing that reducing the amount of fuel we can burn, and so reducing the energy in the cylinders? I don't know- just trying to work out what effect the steam has other than apparently reducing the inlet temp.
bobhatton wrote:ashley wrote:By evaporating water into the inlet tract are we not displacing air, and by doing that reducing the amount of fuel we can burn, and so reducing the energy in the cylinders? I don't know- just trying to work out what effect the steam has other than apparently reducing the inlet temp.
Water will never boil in the inlet manifold, so we will never get steam.
Water expands by 1600 times its volume when changing into steam so would displace large amounts of air
T.F.S. wrote:Its common knowledge that injecting water will cool the intake charge until the charge reaches 100% RH, this is due to evaporative cooling